[1.17.1] Converting resource key to and from string!

[X_ZombieSlayer_X]

How can I convert a resource key to a string(or other serializable type) and then back to a resource key? I need this for storing dimensions for /homes and /warps! Is this even possible?

I read the docs on resource location but I can’t seem to find anything on resource key!

[X_ZombieSlayer_X]

5 hours ago, diesieben07 said:

A ResourceKey is just two ResourceLocations. One for the type of registry and one for the element within that registry. For example:

ResourceKey.create(new ResourceLocation("minecraft", "block"), new ResourceLocation("minecraft", "stone"))

This describes the ResourceKey for the registry entry "minecraft:stone" within the "minecraft:block" registry.

You can serialize a ResourceKey by serializing both ResourceLocations. Or, if you know that it will always be a certain registry, you only need to serialize the 2nd ResourceLocation and fill the other one in when deserializing.

Thanks for the help, I just have one more question. ResourceKey.location only returns one resource location(I believe the registry). How would I get both?(entry and registry)

[X_ZombieSlayer_X]

On 9/6/2021 at 4:43 AM, diesieben07 said:

A ResourceKey is just two ResourceLocations. One for the type of registry and one for the element within that registry. For example:

ResourceKey.create(new ResourceLocation("minecraft", "block"), new ResourceLocation("minecraft", "stone"))

This describes the ResourceKey for the registry entry "minecraft:stone" within the "minecraft:block" registry.

You can serialize a ResourceKey by serializing both ResourceLocations. Or, if you know that it will always be a certain registry, you only need to serialize the 2nd ResourceLocation and fill the other one in when deserializing.

ResourceKey.create(ResourceLocation, ResourceLocation) is not visible. So I am using this!

ResourceKey<Level> dimension = ResourceKey.create(ResourceKey.createRegistryKey(new ResourceLocation(worldRegistry)), new ResourceLocation(worldEntry));