How to remove Vanilla Recipes in 1.12.2?

[Schleim_time]

Hey guys,

I tried something to remove a Vanilla recipe

 

public static void removeRecipes() {
        
             ForgeRegistry<IRecipe> FR = (ForgeRegistry<IRecipe>)ForgeRegistries.RECIPES;
            //ArrayList<IRecipe> recipes = new ArrayList(recipeRegistry.getValues());
            for(IRecipe r : FR) {
                ItemStack I = r.getRecipeOutput();
                if(I != null && I.getItem() == Item.getItemFromBlock(Blocks.CRAFTING_TABLE)) {
                    FR.remove(FR.getKey(r));
                }
            }
    }

 

bud sadly that dont work, i tried a lot of other ways and i searched a lot around the internet and found things like "Craftingmager.getInstance" but that seems only to work for 1.7 :C so does anybody know a solution to that problem? I would be Happy

[V0idWa1k3r]

Wrong subforum.

Don't remove while iterating like that. In most cases you would crash with a CME.

 

Don't access a registry like that.

Remove the recipes during the appropriate registry event.

 

8 minutes ago, Schleim_time said:

I != null

This will always be true.

 

Remove the recipes based on their registry name, not their output.

[Schleim_time]

58 minutes ago, Schleim_time said:

Thank you for your responce, im sorry for the whrong subforum

I got that to remove all crafting recepies, but i dont know how to get something out of the Irecipe to find out which one is the right to remove :C

 

 

@SubscribeEvent
    public static void onRecipeRegister(RegistryEvent.Register<IRecipe> e) {
         ForgeRegistry<IRecipe> FR = (ForgeRegistry<IRecipe>)ForgeRegistries.RECIPES;
         ArrayList<IRecipe> recipe = new ArrayList(FR.getValues());
         for(IRecipe r : recipe) {
             //if(r.toString().contains("wood")) {
             FR.remove(r.getRegistryName());
            
         }
         
    }

 

[V0idWa1k3r]

13 minutes ago, Schleim_time said:

r.toString().contains("wood")

...Why? I told you to remove the recipes based on their registry name. Why are you turning it into a string?

You are even getting said registry name a line lower

[Schleim_time]

It wasnt that hard at end i did

if(r.getRegistryName().toString() == "minecraft:book") {

and that was all, wow and i tried everything else expect that

Thank you very much

[V0idWa1k3r]

Don't compare string instances using ==. Use the equals method.