I have a gun that I want to shoot two bullets: one to a little bit to the left of the player and one a bit to the right. How would I do that?

Construct and spawn 2 entities and simply offset one to right, one to left?

 

What is the problem, show what you tried.

 

More:

EntityThrowable has constructor that takes player as shooter. After constructing entity with that construcor you need to get players look vector and move entity by vector orthogonal to players vector. One Entity to left, one to right.

Thanks.

 

1) how would I make a new vector orthogonal to the players vector?

 

2) would I make two new vectors orthogonal to the second vector at each end to figure out where to spawn the bullets?

On the horizontal plane, I think you can use the rotateAroundY() method in Vec3. rotate by 90 or -90 degrees to get orthogonal.

A simple way to move to the left or right is to take the player's look vector, then subtract the vec.zCoord (* some factor) from the player's posX, and add the vec.xCoord (* some factor) to the player's posZ - that will give you a position directly to the right of the player.

 

Reverse the arithmetic to get a position to the left.

Vec3 vec3 = player.getLookVec();
float f = 0.15F; // this is usually roughly one block width, depending on context; play with it
double dx = player.posX - (vec3.zCoord * f);
double dz = player.posZ + (vec3.xCoord * f);
// now use dx and dz for your entity's position or whatever else