[1.8.9] How to get the position of ender pearl's to be landed place?

[lethinh]

How to get the position of  ender pearl's to be landed place?

[Draco18s]

When?

[lethinh]

12 hours ago, Draco18s said:

When?

When the player is holding it and look at the specific position (to be landed place)

[jabelar]

Did you even look at the ItemEnderPearl class? The code there is quite clear.

 

Anyway that is not really how a throwable works -- it doesn't exactly know where it will land, rather there is math that set its initial velocity such that it travels "naturally" away from the player and then the game physics processes the further movement over successive game ticks. But for example if you look up, where you're looking isn't the same as where it will land.

 

To predict where it would land is pretty difficult. You'd have to simulate it. It is possible -- most people would use an "invisible" entity that you'd shoot at same velocity but would run all the "ticks" within one tick. Note that even then it is possible for the world to change while the ender pearl is in flight and so where it is predicted to land could theoretically not match where it actually lands. 

 

What are you trying to actually do? 

Edited November 22, 2017 by jabelar

[lethinh]

39 minutes ago, jabelar said:

Did you even look at the ItemEnderPearl class? The code there is quite clear.

 

Anyway that is not really how a throwable works -- it doesn't exactly know where it will land, rather there is math that set its initial velocity such that it travels "naturally" away from the player and then the game physics processes the further movement over successive game ticks. But for example if you look up, where you're looking isn't the same as where it will land.

 

To predict where it would land is pretty difficult. You'd have to simulate it. It is possible -- most people would use an "invisible" entity that you'd shoot at same velocity but would run all the "ticks" within one tick. Note that even then it is possible for the world to change while the ender pearl is in flight and so where it is predicted to land could theoretically not match where it actually lands. 

 

What are you trying to actually do? 

 

Yes, I have already looked at ItemEnderPearl and EntityEnderPearl, but no luck. Here is my code: https://pastebin.com/Ff1eXKJk

But it isn't correct, it keeps saying "It is dangerous to throw", I throwed it and I still on the ground (safe)

[Draco18s]

8 hours ago, lethinh said:

 

Yes, I have already looked at ItemEnderPearl and EntityEnderPearl, but no luck. Here is my code: https://pastebin.com/Ff1eXKJk

But it isn't correct, it keeps saying "It is dangerous to throw", I throwed it and I still on the ground (safe)

You haven't simulated anything. You created a new ender pearl entity and then....did nothing with it. You didn't even set its position (so the default values of 0,0,0 apply) and then ask the game "can this location see the sky?" No, no it cannot.