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Featured Replies

Posted

I will check block stone in world.

 

I need to check block stone, if block stone has this world block of mod will can break if block stone hasn't this world block of mod can't break.

 

One more question:

 

If i do mod finish. Where can I post mod of me ?

  • Author

OK I bad english.

 

Sorry

 

I try to communicate you that ->

 

1 I need check block stone in world.

 

2 If world have stone, player can break block of mod.

 

3 If world not have stone, player can't break block of mod.

 

One more question : this question i can't ask you.

 

if possible, you should teach me English. xD

We are not here to teach you English.

 

Your goal is still not clear: stone will exist in the world somewhere.  Checking to see if it exists at a location requires calling World#getBlock(x, y, z) and checking that it equals Blocks.stone

 

Part 2 still makes no sense to me.

Apparently I'm a complete and utter jerk and come to this forum just like to make fun of people, be confrontational, and make your personal life miserable.  If you think this is the case, JUST REPORT ME.  Otherwise you're just going to get reported when you reply to my posts and point it out, because odds are, I was trying to be nice.

 

Exception: If you do not understand Java, I WILL NOT HELP YOU and your thread will get locked.

 

DO NOT PM ME WITH PROBLEMS. No help will be given.

I try to communicate you that ->

1 I need check block stone in world.

2 If world have stone, player can break block of mod.

3 If world not have stone, player can't break block of mod.

 

Possible translations (from "english" to English):

 

1.

I want to check if there is any STONE in world.

If world has at least one STONE block, player will be able to break some modded block in given world.

 

2.

I want to check if there is STONE at given x/y/z in given world.

If there is STONE block at given x/y/z - player will be able to... ??? this wouldn't make sense.

 

Any of those are what you want?

1.7.10 is no longer supported by forge, you are on your own.

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