dye dictionary

[MrArnoEnCo]

hey i wanne make an alternative recipe for whitedye(bone meal) and bluedye(lapis)

but i'm not gonne put all the recipes

i check and you can add an alternative dye thats is linked to the dye you want.

but i don't know how i have to do that and in what file i have to put that

 

 

 

 

this is a part code from the oredictionary file i hope you can help me

 

public class OreDictionary

{

    private static boolean hasInit = false;

    private static int maxID = 0;

    private static HashMap<String, Integer> oreIDs = new HashMap<String, Integer>();

    private static HashMap<Integer, ArrayList<ItemStack>> oreStacks = new HashMap<Integer, ArrayList<ItemStack>>();

   

    static {

        initVanillaEntries();

    }

 

    public static void initVanillaEntries()

    {

        if (!hasInit)

        {

            registerOre("logWood",    new ItemStack(Block.wood, 1, -1));

            registerOre("plankWood",  new ItemStack(Block.planks, 1, -1));

            registerOre("slabWood",    new ItemStack(Block.woodSingleSlab, 1, -1));

            registerOre("stairWood",  Block.stairCompactPlanks);

            registerOre("stairWood",  Block.stairsWoodBirch);

            registerOre("stairWood",  Block.stairsWoodJungle);

            registerOre("stairWood",  Block.stairsWoodSpruce);

            registerOre("stickWood",  Item.stick);

            registerOre("treeSapling", new ItemStack(Block.sapling, 1, -1));

            registerOre("treeLeaves",  new ItemStack(Block.leaves, 1, -1));

        }

 

        // Build our list of items to replace with ore tags

        Map<ItemStack, String> replacements = new HashMap<ItemStack, String>();

        replacements.put(new ItemStack(Block.planks, 1, -1), "plankWood");

        replacements.put(new ItemStack(Item.stick), "stickWood");

 

        // Register dyes

        String[] dyes =

        {

            "dyeBlack",

            "dyeRed",

            "dyeGreen",

            "dyeBrown",

            "dyeBlue",

            "dyePurple",

            "dyeCyan",

            "dyeLightGray",

            "dyeGray",

            "dyePink",

            "dyeLime",

            "dyeYellow",

            "dyeLightBlue",

            "dyeMagenta",

            "dyeOrange",

            "dyeWhite"

        };

 

        for(int i = 0; i < 16; i++)

        {

            ItemStack dye = new ItemStack(Item.dyePowder, 1, i);

            if (!hasInit)

            {

                registerOre(dyes, dye);

            }

            replacements.put(dye, dyes);

        }

        hasInit = true;

 

        ItemStack[] replaceStacks = replacements.keySet().toArray(new ItemStack[0]);

 

 

 

thx, MrArnoEnCo

[ShetiPhian]

If you want the resulting item to be bone meal / lapis

Just set up a standard crafting with the result being  ItemStack(Item.dyePowder, 1, 15) / ItemStack(Item.dyePowder, 1, 4)

 

But if you want the result to be a white / blue dye alternative

Create your item and recipe like normal, then register your item to the ore dictionary

 

OreDictionary.registerOre("dyeWhite", new ItemStack(YOUR_ITEM_ID, 1, WHITE_META));

OreDictionary.registerOre("dyeBlue", new ItemStack(YOUR_ITEM_ID, 1, BLUE_META));

 

Any mod that checks the ore dictionary for dye can use your item.

 

 

http://www.minecraftforge.net/wiki/Ore_dictionary

http://www.minecraftforge.net/wiki/How_to_use_the_ore_dictionary

[MrArnoEnCo]

what is the "WHITE_META"?

[ShetiPhian]

What ever you make it.

 

If you make a new item "myDyes" and set white to meta 0 and blue to meta 1

 

OreDictionary.registerOre("dyeWhite", new ItemStack(myDyes.shiftedIndex, 1, 0));

OreDictionary.registerOre("dyeBlue", new ItemStack(myDyes.shiftedIndex, 1, 1));