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Posted

I cannot invert an explosion. This is what I tried, but it broke the obsidian right after it placed it.

 

public class InvertExplosion {
	public void Explode(Detonate event) {
		for(int i=0; i<event.getAffectedBlocks().size(); i++) {
			BlockPos pos = event.getAffectedBlocks().get(i);
			IBlockState ibs = event.getWorld().getBlockState(pos);
			Block block = ibs.getBlock();
			Block air = Blocks.AIR.getBlockState().getBlock();
			if (!(block==air)) {
				event.getWorld().setBlockState(pos, Blocks.OBSIDIAN.getDefaultState());
			}
		}
	}
}


 

 

The affected blocks list still contains the effected blocks, which will be broken unless you change that list. Just because you turned them into obsidian doesn't change the fact that which blocks will be affected has already been calculated.

Apparently I'm a complete and utter jerk and come to this forum just like to make fun of people, be confrontational, and make your personal life miserable.  If you think this is the case, JUST REPORT ME.  Otherwise you're just going to get reported when you reply to my posts and point it out, because odds are, I was trying to be nice.

 

Exception: If you do not understand Java, I WILL NOT HELP YOU and your thread will get locked.

 

DO NOT PM ME WITH PROBLEMS. No help will be given.

  • Author

Here is my new code:

public class InvertExplosion {
	public void Explode(Detonate event) {
		for(int i=0; i<event.getAffectedBlocks().size(); i++) {
			BlockPos pos = event.getAffectedBlocks().get(i);
			IBlockState ibs = event.getWorld().getBlockState(pos);
			Block block = ibs.getBlock();
			Block air = Blocks.AIR.getBlockState().getBlock();
			if (!(block==air)) {
				event.getWorld().setBlockState(pos, Blocks.OBSIDIAN.getDefaultState());
				event.getAffectedBlocks().remove(i);
			}
		}
	}
}

Somehow a few blocks still got blown up.

Edited by Anonymous1212144

Quote

 

list = [0,1,2,3,4];

for(int i = 0; i < list.size(); i++) {

    list.removeAt(i)

}

 

when i is 0, it removes 0. [(0),1,2,3,4]

when i is 1, it removes 2. [1,(2),3,4]

when i is 2, it removes 4.  [1,3,(4)]

when i is 3, the loop terminates. [1,3].size() < 3

Apparently I'm a complete and utter jerk and come to this forum just like to make fun of people, be confrontational, and make your personal life miserable.  If you think this is the case, JUST REPORT ME.  Otherwise you're just going to get reported when you reply to my posts and point it out, because odds are, I was trying to be nice.

 

Exception: If you do not understand Java, I WILL NOT HELP YOU and your thread will get locked.

 

DO NOT PM ME WITH PROBLEMS. No help will be given.

  • 1 month later...
  • Author
On 1/3/2019 at 9:59 PM, Draco18s said:

when i is 0, it removes 0. [(0),1,2,3,4]

when i is 1, it removes 2. [1,(2),3,4]

when i is 2, it removes 4.  [1,3,(4)]

when i is 3, the loop terminates. [1,3].size() < 3

Thank you! The problem is fixed now!

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