Hi,

So, I'm trying to register a Tile Entity to the game, and I'm using this code:

TILE_ENTITY_TYPES

    public static final DeferredRegister<TileEntityType<?>> TILE_ENTITY_TYPES = DeferredRegister.create(ForgeRegistries.TILE_ENTITIES, "simplycopper");
    public static final RegistryObject<TileEntityType<CopperCoreTileEntity>> COPPER_CORE = TILE_ENTITY_TYPES.register("copper_core", () -> TileEntityType.Builder.create(CopperCoreTileEntity::new, BlockInit.COPPER_CORE).build(null)));

And I get the error: 

Cannot resolve method 'create(<method reference>, net.minecraft.block.Block)'

I have no clue how to fix this.

Here is my CopperCoreTileEntityClass:

Quote

public class CopperCoreTileEntity extends TileEntity {
    public CopperCoreTileEntity(TileEntityType<?> tileEntityTypeIn) {
        super(tileEntityTypeIn);
    }
}

 

Thanks in advance,

Kid Koder

6 minutes ago, KidKoderMod033109 said:

CopperCoreTileEntity::new

^ No parameters specified

 

6 minutes ago, KidKoderMod033109 said:

public CopperCoreTileEntity(TileEntityType<?> tileEntityTypeIn)

^ 1 parameter required

Just now, Draco18s said:

7 minutes ago, KidKoderMod033109 said:

CopperCoreTileEntity::new

^ No parameters specified

 

Oh, I see. How do I pass the parameters. And what do I pass. Do I do TileEntityType<CopperCoreTileEntity>?

No, that means you need to create anothet constructor that has no argument.

Ahh...

But then what do I pass in to the super() method?

Your TileEntity's TileEntityType?

Edited October 16, 20204 yr by Draco18s

But I'm currently registring that Type.

Wait..

No, you're registering a TileEntity with that line. You also, additionally need a TileEntityType.

Edited October 16, 20204 yr by Draco18s

super(new TileEntityType<CopperCoreTileEntity>);

Does that work?

Also,

3 minutes ago, Draco18s said:

No, you're registering a TileEntity with that line. You also, additionally need a TileEntityType.

So how to I register that?

Got it!

        this(ModTileEntityTypes.COPPER_CORE.get());

Works like a charm(I think. No error are preview in IntelliJ)